SCLC Tutorial: Quick start — simulate space-charge limited current
🐝 Under construction: This section is being written and will be updated soon 15/09/2025

Space-charge limited current (SCLC) is the transport regime where injected carriers dominate and the current is limited by their motion through the film, not by generation. In an ideal, trap-free device, the current density follows the Mott–Gurney law: \( J = \frac{9}{8}\,\varepsilon\,\mu\,\frac{V^2}{L^3} \), with dielectric constant \( \varepsilon \), mobility \( \mu \), voltage \( V \), and thickness \( L \). SCLC measurements (often using hole-only or electron-only diodes) are widely used to extract mobility and assess trap effects. In this quick start, you will configure an SCLC structure, run a JV sweep, locate the J ∝ V² region, and see how traps or thickness shift the curve and the extracted mobility.
In ?? we compare contact configurations that control which carriers can enter the device. In panel (a) the standard structure has electron- and hole-selective contacts, creating a built-in potential and allowing both electrons and holes to be injected/extracted. By adjusting the contact energetics or adding/selecting transport/blocking layers, you can enforce single-carrier injection: in panel (b) an electron-only device (SCLC) is formed by providing low barriers to the conduction band at both contacts while blocking the valence band (hole injection), and in panel (c) a hole-only device (SCL) is formed by aligning the valence band at both contacts while blocking the conduction band (electron injection). Compared to the standard device in (a), the single-carrier cases (b,c) suppress recombination and force current to be governed by space-charge-limited transport, which is ideal for extracting carrier mobility and contact effects.
Step 2: Create a new simulation
Start OghmaNano from the Windows Start menu. The main OghmaNano window will appear as shown in ??.


For a trap-free space-charge-limited current (SCLC), the Mott–Gurney law is
$$ J = \frac{9}{8}\,\varepsilon \mu \frac{V^2}{L^3} $$
Rearranging for the mobility:
$$ \mu = \frac{8}{9} \cdot \frac{J L^3}{\varepsilon V^2} $$
Substituting the known values:
- \( L = 100~\text{nm} = 1.0\times10^{-7}~\text{m} \;\;\Rightarrow\;\; L^3 = 1.0\times10^{-21}~\text{m}^3 \)
- \( \varepsilon_r = 3.0 \), \( \varepsilon_0 = 8.85\times10^{-12}~\text{F·m}^{-1} \), so \( \varepsilon = 2.656\times10^{-11}~\text{F·m}^{-1} \)
- \( V = 1.0~\text{V} \)
- \( J \approx 1.0\times10^{3}~\text{A·m}^{-2} \)
Now:
$$ \mu = \frac{8}{9} \cdot \frac{ (1.0\times10^{3})(1.0\times10^{-21}) } { (2.656\times10^{-11})(1.0^2) } = 3.35\times10^{-8}~\text{m}^2\text{V}^{-1}\text{s}^{-1} $$
Or in cgs units:
$$ \mu \approx 3.35\times10^{-4}~\text{cm}^2\text{V}^{-1}\text{s}^{-1} $$